Question

Shown is a top view of a 50-kg person walking on a large horizontal disk, which rotates with constant angular velocity ω0 = 0.3 rad/s. He walks at a constant speed v0 = 5 m/s along a straight line painted on the disk. What is the magnitude of the horizontal force exerted on him by the disk when he is 6 m from the center of the disk? A person is shown walking from the center of a disk.

Answer 1

We are given
m = 50 kg
ω0 = 0.3 rad/s
v0 = 5 m/s
r = 6 m

We are asked for the horizontal force.
Doing a force balance:
Fc = Fh
mω²r = Fh
Substituting
Fh = 50 kg (0.3 rad/s) (6 m)
Fh = 90 N