Question

A particular brand of gasoline has a density of 0.737 g/mL at 25 ∘C. How many grams of this gasoline would fill a 12.3 gal tank (1US gal=3.78L)?

i do not understand how to approach the problem

Answer 1

To find the mass of gasoline needed to fill a 12.3-gallon tank with a density of 0.737 g/mL, the volume is first converted to liters, then to milliliters, and finally, the density is used to calculate the mass, resulting in 34,270.138 grams of gasoline.

Step-by-step explanation:

To calculate the mass of gasoline that would fill a 12.3-gallon tank, given that the density of gasoline is 0.737 g/mL at 25 °C, and knowing that 1 US gallon is equal to 3.78 liters, you would first need to convert gallons to liters.

Here is the calculation process:

First, convert the volume of the gasoline tank from gallons to liters:

12.3 gallons × 3.78 L/gallon = 46.494 liters

Next, convert liters to milliliters, since the density of gasoline is given in g/mL:

46.494 liters × 1,000 mL/liter = 46,494 mL

Finally, use the density of gasoline to find the mass in grams:

0.737 g/mL × 46,494 mL = 34,270.138 g

Therefore, 34,270.138 grams of this particular brand of gasoline would be needed to fill the 12.3-gallon tank.

Answer 2

Its a basic formula of density
Density equals mass in (kg) divided by volume in (L) so now you have both density and volume ( convert the volume to L)
Then find the mass ( but don't forget to convert it to gram at the last step ) ..
if you still don't know how to solve it ask me i will solve it for you .. ツ