Question

If there are 19 plants with rough seeds in a population of 100, what is the allele frequency for smooth seeds?

Answer 1

Therefore 56% of the alleles in this population are smooth alleles, 44% of the alleles are rough alleles.

Answer 2

`0.565\\Or\\56.5`%

Step-by-step explanation:

Given,

Number of plants with rough seed
`= 19`

Total number of plants
`= 100`

Genotype frequency for "plant with rough seed" i.e
`q^(2) \\`
`= (19)/(100) \\= 0.19`

So the allele frequency for "rough seed"
`= \sqrt{q^(2) } \\= √(0.19) \\= 0.435\\`

As per Hardy weinberg equation, we know that sum of allele frequencies around the locus is equal to one .

Thus,

`p+q=1\\`

Substituting the value of q in above equation, we get -

`p+0.435=1\\p = 1-0.435\\p =0.565 \\Or 56.5`%

p represent the frequency of smooth seed.