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Suppose you have 76 feet of fencing to enclose a rectangular dog pen. The function A = 38x – x2, where x = width, gives you the area of the dog pen in square feet. What width gives you the maximum area? What is the maximum area? Round to the nearest tenth as necessary.

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Given that the area is defined by the function

A=38x-x^2

For maximum area,

(dA)/(dx) =0 \\ \\ 38-2x=0 \\ \\ 2x=38 \\ \\ x=19

Therefore, the width that gives the maximum area is 19 feet.

The maximum area is given by

A=38(19)-(19)^2 \\ \\ =19(38-19) \\ \\ =19(19)=361 \ square \, feet.
User Sandip Ghosh
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