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F(x)=x^3-3x-5 between 2 and 8

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\bf slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby \begin{array}{llll} average\ rate\\ of\ change \end{array} \\\\\\ f(x)=x^3-3x-5\quad \begin{cases} x_1=2\\ x_2=8 \end{cases}\implies \cfrac{f(8)-f(2)}{8-2}
User Gluuke
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