Question

Identify the center and radius of the circle with equation (x+2)^2+(y+10)^2=4.

Answer 1

First, rewrite the expression in the form of a standard circle equation.

`\left(x-\left(-2\right)\right)^2+\left(y-\left(-10\right)\right)^2=2^2`
We have our answer:
Center of circle:
`\left(-2,\:-10\right)`

`radius=2`

Have an nice day! :)

Answer 2

`\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad \begin{array}{lllll} center\ (&{{ h}},&{{ k}})\qquad radius=&{{ r}} \end{array}\\\\ -------------------------------\\\\ (x+2)^2+(y+10)^2=4\iff [x-(\underline{-2})]^2+[y-(\underline{-10})]^2=\underline{2}^2`