Question

What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?

Answer 1

molar mass of cuso4=63.5+32+4*16= 159.5 g
6.02*10^23 molecules weigh=159.5 g
1 molecule weigh=159.5/6.02*10^23 g
3.36 × 10^23 molecules weigh=159.5/6.02*10^23*3.36× 10^23
=89.023g

Answer 2

Answer: The mass of given amount of molecules of copper sulfate is 89.054 grams.

Step-by-step explanation:

According to mole concept:

1 mole of a compound contains
`6.022* 10^(23)` number of molecules.

The mass of 1 mole of copper sulfate = 159.609 grams

As,
`6.022* 10^[23}` number of molecules have a mass of 159.609 grams.

So,
`3.36* 10^(23)` number of molecules will have a mass of
`(159.609g)/(6.022* 10^(23))* 3.36* 10^(23)=89.054g`

Thus, the mass of given amount of molecules of copper sulfate is 89.054 grams.