Question

Find: (4x2y3 + 2xy2 – 2y) – (–7x2y3 + 6xy2 – 2y) Place the correct coefficients in the difference.

Answer 1

Answer: 11, -4, 0

(in that order)

(4x2y3 + 2xy2 – 2y) – (–7x2y3 + 6xy2 – 2y)

4-7 =11 (then add the letters and exponents which are x^2y^3)

2+(-6) is -4 add the letters and numbers which are xy^2

-2-(-2) = 0 add the y.

Answer 2

Answer: Our required answer will be

`11x^2y^3-4xy^2`

Explanation:

Since we have given that

`(4x^y^3+2xy^2-2y)-(-7x^2y^3+6xy^2-2y)`

We need to get the difference:

1) We first open the second bracket and make appropriate change in signs :

`4x^y^3+2xy^2-2y+7x^2y^3-6xy^2+2y`

2) Gather the like terms together :

`4x^2y^3+2xy^2-2y+7x^2y^3-6xy^2+2y\\\\=4x^2y^3+7x^2y^3+2xy^2-6xy^2-2y+2y\\\\=11x^2y^3-4xy^2`

Hence, our required answer will be

`11x^2y^3-4xy^2`