Question

A piece of glass with a mass of 32.50 g specific heat of 0.840 J/g*°C and an initial temperature of 75 °C was dropped into a calorimeter containing 57 g of water (specific heat 4.184 J/g*°C). The final temperature of the glass and water in the calorimeter was 79.2 °C. What was the initial temperature of the water?

Answer 1

Hey there,

119.84 degrees c is your answer.

Hope I Helped!

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Answer 2

Answer : The initial temperature of water is,
`79.7^oC`

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

`q_1=-q_2`

`m_1* c_1* (T_f-T_1)=-m_2* c_2* (T_f-T_2)`

where,

`c_1` = specific heat of glass =
`0.840J/g^oC`

`c_2` = specific heat of water =
`4.184J/g^oC`

`m_1` = mass of glass = 32.50 g

`m_2` = mass of water = 57 g

`T_f` = final temperature of mixture =
`79.2^oC`

`T_1` = initial temperature of glass =
`75^oC`

`T_2` = initial temperature of water = ?

Now put all the given values in the above formula, we get:

`32.50g* 0.840J/g^oC* (79.2-75)^oC=-57g* 4.184J/g^oC* (79.2-T_2)^oC`

`T_2=79.7^oC`

Therefore, the initial temperature of water is,
`79.7^oC`