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Which polynomial function has x-intercepts –2, 0, and 1 and passes through the point (2, 16)?

User Daxlerod
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2 Answers

0 votes

Answer:

D. f(x) = 2x^3 + 2x^2 - 4x

User Fareed Radzi
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if it has x intercepts at r1,r2,r3 then the factored form is
f(x)=a(x-r1)(x-r2)(x-r3)
where a is a constant not equal to 0
so
intercepts of -2,0, 1

f(x)=a(x-(-2))(x-0)(x-1)
f(x)=a(x+2)(x)(x-1)
passes through the point (2,16)
find a buy subsituting the point (2,16) into it

16=a(2+2)(2)(2-1)
16=a(4)(2)(1)
16=8a
2=a
the function is
f(x)=2(x+2)(x)(x-1)
User Sambhav Khandelwal
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