Question

Consider the combustion reaction of acetylene (C2H2) : 2C2H2 + 5O2 mc001-1.jpg 4CO2 + 2H2O Use the periodic table to determine how many grams of oxygen would be required to react completely with 859.0 g C2H2?

Answer 1

To react completely with 859.0 g of acetylene, 2639 grams of oxygen gas are required, following the stoichiometric calculation based on the balanced chemical equation of the combustion reaction.

Step-by-step explanation:

The combustion reaction of acetylene (C2H2) requires a certain amount of oxygen to react completely. Using the provided stoichiometric equation, 2C2H2 + 5O2 → 4CO2 + 2H2O, we can determine the mass of oxygen needed by first finding the molar mass of acetylene and oxygen, then using the molar ratio from the balanced equation.

First, calculate the molar mass of acetylene (C2H2):

• Molar mass of C = 12.01 g/mol × 2 = 24.02 g/mol
• Molar mass of H = 1.008 g/mol × 2 = 2.016 g/mol
• Total molar mass of C2H2 = 24.02 g/mol + 2.016 g/mol = 26.036 g/mol

Next, calculate the moles of acetylene in 859.0 g:

• 859.0 g C2H2 ÷ 26.036 g/mol = 32.987 moles of C2H2

Now, use the balanced equation to find the moles of oxygen gas needed:

• According to the equation, 2 moles of C2H2 need 5 moles of O2. Thus, 32.987 moles of C2H2 will need 5/2 × 32.987 moles of O2 = 82.468 moles of O2

Finally, calculate the mass of O2 required:

• Molar mass of O2 = 16.00 g/mol × 2 = 32.00 g/mol
• Total mass of O2 = 82.468 moles × 32.00 g/mol = 2638.976 g of O2

Therefore, 2639 grams of oxygen would be required to react completely with 859.0 g C2H2.

Answer 2

2643.08g of O2

Step-by-step explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Step 2:

Determination of the masses of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Molar Mass of C2H2 = (12x2) + (2x1) = 24 + 2 = 26g/mol

Mass of C2H2 from the balanced equation = 2 x 26 = 52g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 5 x 32 = 160g

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Step 3:

Determination of the mass of oxygen that would be required to react completely with 859.0g of C2H2.

This is illustrated below:

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Therefore, 859g of C2H2 will react with = (859 x 160)/52 = 2643.08g of O2.

From the calculations made above, 2643.08g of O2 will react completely with 895g of C2H2.