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If i hold a glass full of air upside down, and i take it to the bottom of the swimming pool without tipping it, the density (thickness) of the air inside the glass will be ________ at the surface.

2 Answers

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Final answer:

The density of the air inside the glass will remain the same at the surface.

Step-by-step explanation:

When you hold a glass full of air upside down and take it to the bottom of a swimming pool without tipping it, the density of the air inside the glass will remain the same at the surface. This is because density does not change with depth in a static fluid. The pressure at any point in a static fluid depends only on the depth at that point, not on the density of the fluid. In the case of a swimming pool, the density of the water is approximately constant, so the density of the air inside the glass will also be constant at the surface.

User Izy
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The answer to fill in the blank in the question above is "greater than" based on the physic of the air density. The density of air is affected by the temperature and the pressure based on the ideal gas law. A high pressure will make the air becomes denser and the bottom of swimming pool has a higher pressure than the surface.
User Ceexon
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