Question

How do I solve log(2)t^3-1=-3?

Answer 1

assuming you mean

`log_2(t^3-1)=-3`
remember

`log_a(b)=c` translates to
`a^c=b`
translate


`log_2(t^3-1)=-3` translates to
`2^(-3)=t^3-1`

`(1)/(2^3) =t^3-1`

`(1)/(8) =t^3-1`
add 1 to both sides

`(9)/(8) =t^3`
cube root both sides

`\frac{ \sqrt[3]{9} }{2}=t`