Question

A country's population in 1993 was 72 million. In 1996 it was 76 million. Estimate the population in 2003 using the exponential growth formula. Round your answer to the nearest million?

Answer 1

Hi there
First find the rate of growth
The formula is
P=Ae^kt
P 76 million
A 72 million
E constant
K ?
T 1,996−1,993=3 years
We need to solve for k
K=[log (p/A)÷log (e)]÷t
K=(log(76÷72)÷log(e))÷3
K=0.018

Now find the population in 2003
P=Ae^kt
P ?
A 72 million
K 0.018
T 2,003−1,993=10 years
So
P=72×e^(0.018×10)
P=86 million

Hope it helps