1) f(x) = 2 - x^12
2) g(x) = x^2 - 9
3)
g(x) 2 - x^12
g(x)÷f(x) = -------- = ------------
f(x) x^2 - 9
The domain of g(x)÷f(x) is all the x values where the function is defined.
It is defined for all x where the denominator is different of zero.
So, find where x^2 - 9 = 0.
That is x = 3 and x = -3.
And the domain is all the real numbers except x = 3 and x = -3.