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A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter at a speed of 6.0 meters/second. What is the emf produced? 5.1 volts 6.9 volts
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A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter at a speed of 6.0 meters/second. What is the emf produced?

5.1 volts
6.9 volts
0.0050 volts
0.18 volts
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User Rajamohan S
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7.6k points

2 Answers

4 votes

Answer:d

Step-by-step explanation:

User Chagbert
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8.8k points
4 votes
The emf induced = B*l*v where B is the flux density, l the length of the conductor and v the velocity of the conductor. In the given case B = 0.035 N/amp.meter, l = 0.86 and v = 6 m/sec
emf = 0.035*0.86*6 = 0.1806 v ≈ 0.18 v
choice: D
User Rizu
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8.2k points
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