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Y = – 3 y = x – 0.8 What is the best approximation for the solution to this system of equations?

User Slhck
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Then the vertex is at (h, k) = (2, –3) and the value of p is –3. Since y is squared and p is negative, then this is a sideways parabola that opens to the left. This puts the focus 3 units to the left of the vertex.

vertex: (2, –3); focus: (–1, –3)

User Sreyas
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