Question

A 42 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.124. Find the substance's half-life, in days. Round your answer to the nearest tenth.

Answer 1

k = natural log (.5) / Half-Life
0.124 = .693147 / Half-Life
Half-Life = .693147 / 0.124
Half-Life = 5.5898951613 days

Answer 2

Half life of sample = 5.59 days

Explanation:

We have the equation for half life

`t_(1)/(2)=(ln2)/(k)`

Here decay constant k = 0.124

Substituting

`t_(1)/(2)=(ln2)/(0.124)=5.59\boldsymbol{\texttt{ days}}`