Question

A particle decays at a rate of 0.45% annually. assume and initial amount of 300 mg. (

a. how much of the particle remains after 60 years? (
b. what is the half-life of the particle?

Answer 1

The increase is an exponential increase in a multiplier

`100%+0.45%=100.45%` and as decimal 1.0045

Final Value = Initial Value ×
`multiplier^(number of years)`
Final value =
`300(1.0045)^(60)`
Final value = 393 mg (to the nearest whole number)

Half life = 0.5 years
Final value =
`300(1.0045)^(0.5)`=301 mg