Question

330 g of water at 55°c are poured into an 855 g aluminum container with an initial temperature of 10°

c. the specific heat of aluminum is what is the final temperature of the system, assuming no heat is exchanged with the surroundings?

Answer 1

the final temperature of the system is 32.5°
we know, H = mcT
where, H = Heat content of the body
m = Mass,
c = Specific heat
T = Change in temperature
According to to the Principle of Calorimetry

The net heat remains constant i.e.
⇒ the heat given by water = heat accepted by the aluminum container.
⇒ 330 x 1 x (45 - T) = 855 x
`(900)/(4200)` x (T - 10)

⇒ 14,850 - 330T = 183.21T - 1832

⇒ - 513.21 T = - 16682

or T = 32.5°