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Can someone please help me? -r/3 ≤ 6

Can someone please help me? -r/3 ≤ 6
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4 votes
Can someone please help me?

-r/3 ≤ 6

User Dkruchok
by
8.5k points

1 Answer

4 votes
the answer would be
r \geq 2
User Susparsy
by
8.8k points
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