Question

The perimeter of a rectangle is 40 inches. If the length is four less than twice the width, find the dimensions and area

Answer 1

L = 12 inches and W = 8 inches

Area = 96 in^2

Explanation:

Perimeter(P) = 2(width) + 2(length)

Let W = width and L = length

P = 2W + 2L

L = 2W - 4

Substitute: P = 2W + 2(2W - 4)

P = 6W - 8

P = 40 inches

40 = 6W - 8

6W = 48

W = 8

L = 2W - 4

L = 2(8) - 4

L = 12

L = 12 inches and W = 8 inches

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Check to see if this works:

P = 2W + 2L

P = 2(12) + 2(8)

P = 24 + 16

P = 40 inches YES

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Area = WxL

Area = (12)*(8)

Area = 96 in^2