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Find the x-intercepts of the parabola with vertex (1, -9) and y intercept at (0, -6).

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hello :
the parabola's equation is : f(x) = a(x-1)²-9
the coefficient of the squared expression in the parabola's equation is : a
but ; f(0) = -6 ... (
y-intercepts (0,-6) )

-6 = a(0-1)²-9
-6 =a -9


a=3
f(x) = 3(x-1)²-9

the x-intercepts when : f(x) =0
3(x-1)²-9 =0
(x-1)² =3
x-1 = √3) or x-1 = -√3)

x= 1 +√3 or x= 1 -√3 are the x-intercepts
User Alexey Tseitlin
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