The root sof this quadratic equation are -4 and 2.5.
The roots of any quadratic can be found by using the quadratic equation. The equation is below for you.

In this equation you use the number attached to x^2 as the a, which in this case is -2. The number attached to x as b, which is in this case -3. And the number at the end as c, which is 20. From there you solve for the answers.



Now you separate and get the two separate answers. First the positive.


4
Now the negative


-2.5