The length of a rectangle is 2 more than three times the width. The area of the rectangle is 161 square inches. What are the dimensions of the rectangle? If x = the width of the rectangle, which of the following equations is used in the process of solving this problem? 2x2 + 3x - 161 = 0 3x2 + 2x - 161 = 0 6x2 - 161 = 0