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How many atoms are in 2.5 moles of beryllium atoms?

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as we know that there are avogadro no. of atoms in 9 g of beryllium.
1 mole of beryllium = 6.02 * 10^23 atoms
so 2.5 mole= 6.02*10^23*2.5 i.e = 15.055 × 10^23 atoms
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