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The angles of a triangle are in the ratio 11 : 5 : 2. The side opposite the largest angle is 5.5 centimeters. The length of the side opposite the smallest angle of the triangle is ? centimeters

User Tjwrona
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1 vote

Answer:

2.00

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User Mandar Shinde
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3 votes

Answer:

The length of the side opposite the smallest angle of the triangle is 2 centimeter.

Explanation:

Given : The angles of a triangle are in the ratio 11 : 5 : 2. The side opposite the largest angle is 5.5 centimeters.

To find: The length of the side opposite the smallest angle of the triangle is?

Solution :

Let x be the angle of the triangle.

The angles of a triangle are in the ratio 11 : 5 : 2.

Sum of angles of the triangle is 180°.

So,
11x + 5x + 2x = 180


18x = 180


x=10

Therefore, The angles of the triangles are 110, 50,20 degrees.

Now, Applying Law of Sines:

i.e, to find the remaining sides of a triangle when two angles and a side are known we apply,


(\sin A)/(a)=(\sin B)/(b)

Let A=110°(as largest angle), a=5.5 cm(given)

B=20° (as 20 is the smallest angle), b=b(smallest length)

Substitute,


(\sin 110)/(5.5)=(\sin 20)/(b)

Cross multiply,


b=(\sin 20* 5.5)/(\sin 110)


b=2.00

Therefore, The length of the side opposite the smallest angle of the triangle is 2 centimeter.

User Palaniichuk Dmytro
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