Answer:
Percentage Yield = 89.39 %
Step-by-step explanation:
First thing's first, we have to write down the balanced chemical equation;
CH4(g) + 2 O2(g) --> CO2(g) + 2 H2O(g)
It is crucial we identify the limiting reactant before proceeding. The limiting reactant tells us which reactant is the reaction dependent on and how much of the product can be obtained. We calculate it using the following steps;
1. Calculate the number of moles of each reactant present
Methane - Number of moles = mass / molar mass = 8.50 / 16 = 0.53125 mol
Oxygen - Number of moles = mass / molar mass = 15.9 / 32 = 0.4969 mol
2. Divide the actual number of moles of each reactant by its stoichiometric coefficient in the balanced chemical equation:
Methane - 0.53125 / 1 = 0.53125
Oxygen - 0.4969 / 2 = 0.24845
3. The reactant with the smallest mole ratio is limiting. The limiting reactant is oxygen.
Since the product we are interested in is the Carbon dioxide, From the equation, we have;
2 mol of O2 reacts to produce 1 mol of CO2.
Expressing in terms of mass; Mass = Number of moles * Molar mass
64g ( 2 * 32) = 44g ( 1* 44)
15.9 g = x
Upon solving for x;
x = (15.9 * 44) / 64
x = 10.93
Theoretical Yield = 10.93g
Practical Yield = 9.77g
Percentage Yield = (Practical Yield / Theoretical Yield) * 100
Percentage Yield = ( 9.77 / 10.93 ) * 100
Percentage Yield = 89.39%