Answer:
and

Explanation:
Here are given a point (2,36) and find out the exponential function which passes through this point.
In order to do so , we first check the standard form of an exponential form.
The standard form is given as

Now if point (2,36) lies on graph of this function , it must satisfies the equation of function . Hence let us substitute x=2 and y = 36 in our standard form.

Now taking square roots on each sides we get
and

Hence our exponential functions are
and
