Question

Find the rate of change of the function h(x) = 4x – 3 on the interval 0 ≤ x ≤ 1.

The rate of change is
a0.

Answer 1

Rate of change of function is slope 4.

Explanation:

Given the function h(x) = 4x - 3 on the interval 0 ≤ x ≤ 1.

we have to find the rate of change of function.

h(0)=4(0)-3=-3

h(1)=4(1)-3=4-3=1

`\text{Rate of change=}(h(t_2)-h(t_1))/(t_2-t_1)\\\\=(h(1)-h(0))/(1-0)=(1-(-3))/(1-0)=4\\`

Hence, Rate of change of function is slope 4.

Answer 2

At x = 0
h(0) = 4(0) - 3 = -3

At x = 1
h(1) = 4(1) - 3 = 1

The rate of change is
ROC = [1 - (-3)] / [ `1 - 0 ]
ROC = 4