Question

Find the radius and center of the circle given by the equation below.

(x – 6)2 + (y + 4)2 = 7

A. r = 7 and center at (-6, 4)

B. r = 7 and center at (6, -4)

C. r = √7 and center at (-4, 6)

D. r = √7 and (6, -4)

Answer 1

the answer to your question is b

Answer 2

D. r = √7 and (6, -4)

Explanation:

Since, the standard equation of a circle is,

`(x-h)^2+(y-k)^2=r^2`

Where, (h,k) is the center of the circle and r is the radius of the circle,

Here, the given equation of the circle,

`(x-6)^2+(y+4)^2=7`

`\implies (x-6)^2+(y-(-4))^2=(√(7))^2`

By comparing,

The radius of the circle, r = √7 unit,

And, center = (6,-4)

Hence, option 'D' is correct.