Register
Find number of oxygen atoms in 0.25mole of ca3(po4)2
121k views
1 vote
Find number of oxygen atoms in 0.25mole of ca3(po4)2

User Ralf Wickum
by
7.5k points

1 Answer

3 votes
n(Ca₃(PO₄)₂)=0.25 mol

n(O)=8n(Ca₃(PO₄)₂)

N(O)=Nₐn(O)=8Nₐn(Ca₃(PO₄)₂)

N(O)=8*6.022*10²³ mol⁻¹*0.25 mol=1.2044*10²⁴
User Gnovice
by
7.8k points
← Prev Question Next Question →

Related questions

User Paramvir Singh
asked Jun 11, 2024 146k views
Identify the compound that is base-insoluble. NaCl Bi2S3 PbCl2 MnS Ca3(PO4)2
Paramvir Singh asked Jun 11, 2024
by Paramvir Singh
7.8k points
2 answers
2 votes
146k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
What is the evidence of a chemical reaction when the fireworks go off
Link Copied!