Question

There are two spinners. The first spinner has three equal sectors labeled 1, 2 and 3. The second spinner has four equal sectors labeled 3, 4, 5 and 6. The spinners are spun once. What is the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner?

2
6
9
12

Answer 1

Answer: First option is correct.

Explanation:

Since we have given that

the first spinner has three equal sectors labelled 1, 2 and 3

The second spinner has four equal sectors labelled 3, 4, 5 and 6.

Sample space will be

`{(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5),(2,6),(3,3),(3,4),(3,5),(3,6)}`

So, Number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner :

As we can see that there are 2 such outcomes where we can get the above condition i.e. (2,4) and (3,4).

Hence, First option is correct.

Answer 2

The number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

Spinner 1 Spinner 2
1 1
1 2
1 3
1 4
2 1
2 2
2 3
2 4 = NOT 1, AND 4
3 1
3 2
3 3
3 4 = NOT 1, AND 4

Only 2 outcomes have passed the given condition.