Question

Find the perimeter of the following shape: Shape ABCD is shown. Point A is at 7, 5. Point B is at 6, 3. Point C is at 3, 2. Point D is at 4, 4. 10.8 11 11.4 11.6

Answer 1

10.8

Explanation:

Answer 2

A. 10.8.

Explanation:

We are given that a shape ABCD . The point A is (7,5), B (6,3), C(3,2) and D (4,4).

By using distance formula we find sides of given shape and then find perimeter.

Distance formula:The distance between two points
`(x_1,y_1)`and
`(x_2,y_2)`

=
`√((x_2-x_1)^2+(y_2-y_1)^2)`

Length of side AB=
`√((6-7)^2+(3-5)^2)=√(1+4)`

Length of side AB=
`\sqrt5`units

Length of BC=
`√((3-6)^2+(2-3)^2)=√(9+1)`

Length of side BC=
`√(10)` units

Length of side CD=
`√((4-3)^2+(4-2)^2)=√(1+4)`

Length of side CD=
`\sqrt5`

Length of side AD=
`√((4-7)^2+(4-5))=√(9+1)`

Length of side AD=
`√(10)`

Therefore, the perimeter of given shape ABCD=AB+BC+CD+AD

The perimeter of given shape ABCD=
`\sqrt5+√(10)+\sqrt5+√(10)`

The perimeter of given shape ABCD=
`2\sqrt5+2√(10)=2* 2.23+2* 3.16`.

Substitute
`\sqrt5=2.23,√(10)=3.16`

The perimeter of given shape=4.46+6.32

The perimeter of given shape=10.78=10.8(round off)

Hence, the perimeter of given shape=10.8 units

Therefore, option A is correct.