Question

Jean bought a bag of candy that contained red candies, green candies, and brown candies. Some candies are marked with a smile, and others are not marked. The probabilities are displayed in the table below:   Red Green Brown Smile 0.10 0.30 0.10 No smile 0.20 0.15 0.15 If a random candy is chosen from this bag, what is the probability that the candy was red or had no smile?

Answer 1

The probability of choosing red or no smile = 0.10 + 0.50 = 0.60


Hope this helps!

Answer 2

Answer: 0.60

Step-by-step explanation: A:candy is red

P(A)=0.10+0.20=0.30

B:candy had no smile

P(B)+0.20+0.15+0.15=0.50

A∪B:candy is red or had no smile

P(A∪B) we have to find

A∩B:candy is red and had no smile

P(A∩B)=0.20

P(A∪B)=P(A)+P(B)-P(A∩B)

P(A∪B)=0.30+0.50-0.20

= 0.60

hence, probability that candy was red or had no smile=0.60