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Copper atoms are oxidised at the positive electrode to Cu2+ ions, as shown in the half equation. Cu(s) Cu2+(aq) + 2e− (i) How does the half equation show that copper atoms are oxidised?
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Copper atoms are oxidised at the positive electrode to Cu2+ ions, as shown in the half equation.

Cu(s) Cu2+(aq) + 2e−
(i) How does the half equation show that copper atoms are oxidised?

User JaviAlgaba
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1 Answer

3 votes
Oxidation state changes reflect charges of atoms
Cu2+(aq) has an oxidation state of 2, while Cu(s) has an oxidation state of 0.
So, Cu(s)=Cu2+(aq)+2e->>>(2+(-2))=Cu
User Deekshith Bellare
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