Question

If a car goes along a straight road heading east and speeds up from 45 ft/s to 60 ft/s in 5 s calculate the acceleration

Answer 1

Acceleration is 3 f/ts
you subtract then divide
(45-60)/5

Answer 2

`3\ ft/s^2.`

Step-by-step explanation:

It is given that initial speed of car,
`v_i=45\ ft/s.`

Also, final speed of car,
`v_f=60\ ft/s.`

Time taken by the car during this process,
`t=5\ s.`

We need to find the acceleration of car, a.

Now, by newton's equation of motion.

We know,
`v_f-v_i=a* t`

Putting all required values in above equation.

`60-45=5* a.\\a=3\ ft/s^2.`

Therefore, the acceleration by the car during this process is
`3\ ft/s^2.`

Hence, it is the required solution.