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In the reaction Mg (s) + 2HCl (aq) -> H2 (g) + MgCl2 (aq), how many grams of hydrogen gas will be produced from 300 milliliters of a 4 M HCl in an excess of Mg? Please show all work
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Feb 24, 2018
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In the reaction Mg (s) + 2HCl (aq) -> H2 (g) + MgCl2 (aq), how many grams of hydrogen gas will be produced from 300 milliliters of a 4 M HCl in an excess of Mg? Please show all work
Chemistry
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JPvdMerwe
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Mg(s) + 2HCl(aq) = H₂(g) + MgCl₂(aq)
v=300 ml=0.3 l
c=4 mol/l
n(HCl)=vc
m(H₂)/M(H₂)=n(HCl)/2
m(H₂)=M(H₂)vc/2
m(H₂)=2.0g/mol·0.3 l · 4mol/l /2 = 1.2 g
1.2 grams of hydrogen gas will be produced
Christer Nordvik
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Mar 2, 2018
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