Question

For a cell whose potential is –0.46 v with 3 moles of electrons exchanged, what is ΔG ? ΔG = –nFE°cell

Answer 1

133kj

Step-by-step explanation:

Answer 2

ΔG is 133kJ

ΔG = –nFE°cell
ΔG = free energy of the reaction = ?
n = no of moles of electrons exchanged in the reaction = 3
F = Faraday's constant (9.648456 x
`10^(4)`C/mol)
`E_(0)` = cell potential = –0.46 v

⇒ ΔG = –nFE°cell
⇒ ΔG = - (3 mol)(9.648456 x
`10^(4)` C/mol) (-0.46 J/C) ⇒ ΔG = +133148 J ≈ 133 kJ