63.5k views
4 votes
Saturn orbits the Sun at a distance of 1.43 × 1012 m. The mass of the Sun is 1.99 × 1030 kg.

Use to determine Saturn’s orbital period in Earth years. Is it:
A)29.6 Earth years
B)296 Earth years
C)874 Earth years

User AlexSh
by
7.9k points

2 Answers

2 votes

The answer is A 29.6 Earth Years

User Commandiron
by
7.5k points
7 votes

Answer:

Saturn’s orbital period is 29.6 years

Explanation:

It is given that,

The mass of the sun, m = 1.99 × 10³⁰ kg

Saturn orbits the sun at a distance of, a = 1.43 × 10¹² m

Using third law of Kepler's :


T^2=(4\pi^2)/(GM)a^3

Where,

T is the orbital time period

G is the universal gravitational constant

M is the mass of the sun

a is the distance

So,
T^2=(4(3.14)^2)/(6.67* 10^(-11)* 1.99* 10^(30))(1.43* 10^(12))^3


T=\sqrt{8.688* 10^(17)}\ s


T=932094415.818\ s

To convert seconds into year divide the time by 3.154 × 10⁷

So, T = 29.55 Years

or T = 29.6 Years

Hence, the Saturn's orbital period is 29.6 Earth years

User Amirlazarovich
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.