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Convert 345 NH3 grams to moles
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Convert 345 NH3 grams to moles

User Willem Renzema
by
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2 Answers

1 vote
m(NH₃)=345 g

M(NH₃)=A(N)+3A(H)
M(NH₃)=14.0+3·1.0=17.0g/mol

n(NH₃)=m(NH₃)/M(NH₃)

n(NH₃)=345g/17.0g/mol=20.3 mol
User Bharat Kul Ratan
by
6.5k points
2 votes
345 NH3 in moles is: 20.2577490294015 moles.
User Derwyn
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6.8k points
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