y=-2x+2 and y=x^2-3x.
If there are solutions the x and y values are equal so we can say y=y:
x^2-3x=-2x+2 add 2x to both sides
x^2-x=2 subtract 2 from both sides
x^2-x-2=0 now factor...
x^2+x-2x-2=0
x(x+1)-2(x+1)=0
(x-2)(x+1)=0
So there are two solutions, when x=-1 and 2
Using y=-2x+2 we can find the corresponding y values for the solutions...
y(-1)=-2(-1)+2=2+2=4, y(2)=-2(2)+2=-4+2=-2 so the two solutions are the points:
(-1,4) and (2,-2)