Question

The length of a rectangle is 2 more than twice the width. Find the dimensions of the rectangle if the perimeter is 76.

Answer 1

Let the width be x
Width: x
Lenght: 2x + 2

perimeter of a rectangle: (2 × width) + (2 x lenght)
P: 2(x) + 2(2x +2)

perimeter: 76

76 = 2(x) + 2(2x + 2)
76 = 2x + 4x + 4
72 = 2x + 4x
72 = 6x
12 = x

Width of the rectangle: 12

Lenght of the rectangle: (2 x 12 + 2)
= 24 + 2
= 26