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Find the values of x and y that produce the following Pythagorean triples :
1.) 65, 72, 97
2.) 25, 312, 313
3.) 39, 760, 761

Please show work if you can!

User Itsmikem
by
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1 Answer

4 votes
Let
x and
y be two legs of a right triangle. By Pythagoras' theorem, the hypotenuse will have length
√(x^2+y^2):


x^2+y^2=(√(x^2+y^2))^2

What you should do is read the first two values in the given lists as
x and
y, and the third as
√(x^2+y^2).

So for example, if I gave you the list 3, 4, 5, we take


x=3

y=4

\implies√(x^2+y^2)=√(9+16)=√(25)=5

Since
√(x^2+y^2)=x^2+y^2, it follows that (3, 4, 5) is indeed a Pythagorean triple.

Let's check with the first problem: If
x=65 and
y=72, we have


√(x^2+y^2)=√(9409)=97

which means (65, 72, 97) is also a Pythagorean triple.
User Daniel Torres
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7.1k points