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Given a rectangle with the following dimensions: Area = 50 units Length = x + 10 units Width = x units Find the value of x.

User Paul Vernon
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1 Answer

15 votes
15 votes

Explanation:

the area of a triangle is

length × width

in our case

(x + 10) × x = 50

x² + 10x = 50

x² + 10x - 50 = 0

the general solution to such a quadratic equation

ax² + bx + c = 0

is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case that is

x = (-10 ± sqrt(10² - 4×1×-50))/(2×1) =

= (-10 ± sqrt(100 + 200))/2 =

= (-10 ± sqrt(300))/2 = (-10 ± sqrt(100×3))/2 =

= -5 ± sqrt(100×3/4) = -5 ± sqrt(25×3) =

= -5 ± 5×sqrt(3)

x1 = -5 + 5×sqrt(3) = 3.660254038...

x2 = -5 - 5×sqrt(3) = -13.66025404...

x2 gives us negative values for length and width. that does not make any sense for actual lengths of objects.

so,

x = 3.660254038...

User Delby
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3.2k points