Question

Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula? Quadratic formula: x =

Answer 1

`x=(2\pm√(76))/(-6)`

Explanation:

Given : Equation
`-3x^2-2x+6=0`

To find : The correct substitution of the the values a, b, and c from the equation into quadratic formula?

Solution :

The general form of the quadratic equation is
`ax^2+bx+c=0`

Where, a is the coefficient of
`x^2`

b is the coefficient of x

c is the constant term.

On comparing with
`-3x^2-2x+6=0`

a=-3 , b=-2 , c=6

The quadratic formula of the quadratic equation is given by,

`x=(-b\pm√(b^2-4ac))/(2a)`

Substituting the values,

`x=(-(-2)\pm√((-2)^2-4(-3)(6)))/(2(-3))`

`x=(2\pm√(4+72))/(-6)`

`x=(2\pm√(76))/(-6)`

So, The required formula which shows the correct substitution of the values.