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There are 3 quarters, 4 dimes and 7 nickels in a change purse. Suppose 3 coins are selected without replacement. What is the probability of selecting a quarter, then a dime, and…
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There are 3 quarters, 4 dimes and 7 nickels in a change purse. Suppose 3 coins are selected without replacement. What is the probability of selecting a quarter, then a dime, and…
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Jan 2, 2018
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There are 3 quarters, 4 dimes and 7 nickels in a change purse. Suppose 3 coins are selected without replacement. What is the probability of selecting a quarter, then a dime, and then a nickel?
Mathematics
high-school
Yami Odymel
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0.037%
How I did it:
I did 3/13, and got 0.23, I didn't do 14 because if its going to be chosen, its going to have one less, and I did the same for the other ones. Then I simply just multiplied them.
Bob Probst
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Jan 4, 2018
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Bob Probst
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prob of just quarter is 3/14 for a dime is 4/14 and for a nickel its 7/14
then all you do is multiply them all together to get 306122449/
10000000000 that took me way to long
Kinopyo
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Jan 8, 2018
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