Answer: P(X=0) = 1/4, P(X=1)=1/2 and P(X=2)= 1/4.
Explanation:
Since, the possible genders of the children is S = {BB, BG, GB, GG}
Here, Let X represent the number of times G occurs.
Thus, when there is no girl
Possible arrangement = {BB}
Then P(X=0) = 1/4
When there is one girl,
Then possible arrangement = { BG, GB}
Thus P(X=1)= 2/4
⇒ P(X=1)=1/2
When there is 2 girls,
Then possible arrangement = {GG}
Thus P(X=2)= 1/4