Part A)
Add up the probability values to get:
0.09+0.36+0.35+0.13+0.05+0.02 = 1
since we get 1 as a result, this confirms we have a legitimate probability distribution.
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Part B)
The notation P(X > 2) translates to "the probability that X is larger than 2". In this problem's context, it means "the probability of choosing a family that owns more than 2 cars"
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Part C)
P(X = 2) means "the probability that X is equal to 2"
Specifically for this problem it means "the probability of picking a family with exactly 2 cars".
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Part D)
Let
A = probability that the family owns exactly 0 cars = 0.09
B = probability that the family owns exactly 1 cars = 0.36
C = probability that the family owns exactly 2 cars = 0.35
D = probability that the family owns exactly 3 cars = 0.13
E = probability that the family owns exactly 4 cars = 0.05
F = probability that the family owns exactly 5 cars = 0.02
Add up the probabilities D, E, and F to compute P(X > 2)
P(X > 2) = probability that the family owns more than 2 cars
P(X > 2) = D + E + F
P(X > 2) = 0.13+0.05+0.02
P(X > 2) = 0.2