104k views
0 votes
a pentegon can be divided into five congruent triangles as shown. the function y=5 tan theta models the height of each triangle. what is the area of the pentagon if theta=54 degrees?

User Kathan
by
6.4k points

2 Answers

0 votes

The answer is:


172
ft^2

User Mmhan
by
6.6k points
4 votes
We are required to calculate the area of the pentagon whose height is given by y=5 tan theta
where; theta=54°
but
tan theta=[opposite]/[adjacent]
thus
opposite=adjacent tan theta
since
5tan54=opposite
adjacent=5
Therefore the base of the pentagon will be
(5+5)=10
Area of a triangle is given by:
A=1/2(base*height)sin theta
The area of one triangle forming the pentagon will be:
A=1/2*(10*5tan54)*sin54
A=27.84 square units
Thus the area of pentagon will be:
Area=(# triangles)*(area of one triangle)
=27.84*5
=139.2 square units
User Hollystyles
by
7.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.